Transendentale funksjonar

Introduksjon

Hans Georg Schaathun

August 2016

$$f_1(x) = x^5 + x^2 - 5x - 1$$

$${f_2(x)} = \frac{x^5 + x^2 - 5x - 1}{x^3+x+1}$$

$${f_3(x)} = \sqrt{\frac{x^5 + x^2 - 5x - 1}{x^3+x+1}}$$

$$f_4(x) = \sin x$$

$$f_5(x) = 2^x$$